Question

a função f:={-2,-1,0,1,2} => R é definida por y=x^2-1 então:
a)D(f)={0,1,2}
b)D(f)={-2,-1,1,2}
c)Im(f)={-1,0,3}
d)im(f)={-5,-2,-1,0,3}

Answer 1

$Resolu\c{c}\~ao\to \left\{\begin{array}{ccc}f:\{-2,-1,0,1,2\}\\y = x^2-1\\\\y = (-2)^2-1 = 4-1 = 3\\\\y = (-1)^2-1 = 1-1 = 0\\\\y = 0^2-1 = -1\\\\y = 1^2-1 = 0\\\\y = (2)^2-1 = 4-1 = 3\\\\\boxed{\boxed{Im(f) = \{-1,0,3\}}}\to Letra\ C\end{array}\right$

Espero ter ajudado. :))