Question

resolvam

1) 3x+9=18



2) 2x(x+9)



3) x+12=10

Answer 1

1)
$3x + 9 = 18 \\ 3x = 18 - 9 \\ 3x = 9 \\ x = 9 \div 3 \\ x = 3$


2)
$2x(x + 9) = \\ 2x ^{2} + 18x =$
3)
$x + 12 = 10 \\ x = 10 - 12 \\ x = - 2 \\ x = - 2( - 1) \\ x = 2$