Question

Qual é a fração geratriz de a)0,222..., b)0,1212..., c)0,321321...,d) 0,333...e)0,34545...f)0,23131...

Answer 1

a) 0,222 = $\frac{2}{9}$

b)0,12 = $\frac{12}{99}$

c)0,321 = $\frac{321}{999}$

d)0,333 = $\frac{3}{9}$

e)0,34545 = $\frac{34545}{99999}$

f)0,23131 = $\frac{23131}{99999}$

Answer 2

a)0,222...= 2/9
b)0,1212...=12/99=4/33
c)0,321321...321/999=107/333
d)0,333...=3/999=1/333
e)0,34545...=345-3=342/990=114/330=38/110=19/55
f)0,23131...231-2/999=229/999.