Question

me ajudem a resolver esses calvulos por favor alguem ai sabe ?

Answer 1

$Resolu\c{c}\~ao \to \left\{\begin{array}{ccc}(2,5,9,14,20,27)\\\\a)\ a_1-2*a_5 = 2-2*20 = 2-40 = -38\\\\b)\ a_4-3*a_1 = 14-3*2 = 14-6 = 8\\\\c)\ S_n = 2+5+9+14+20+27 = 77 \end{array}\right$

Espero ter ajudado. :))

Answer 2

Olá Lara, 
$a) a_{1} - 2 * a_{5} = 2 - 2 * 20 = -38 b) a_{4} - 3* a_{1} = 14 - 3*2 = 8 c) Soma total = ( S_{n} ) = 2+5+9+14+20+27 = 47 + 30 = 77.$