Question

Dada a funçao y=x²-3x+2 calcule as suas raizes

Answer 1

y= x² -3x + 2

a=1
b=-3
c=2

Δ=b²-4ac
Δ= (-3)²-4(1)(2)
Δ= 9 -8
Δ= 1

$x= \frac{-b\pm \sqrt{\Delta} }{2a} = \frac{-(-3)\pm \sqrt{1} }{2} = \frac{3\pm1}{2} \\ \\ x'= \frac{3+1}{2} = \frac{4}{2} =2 \\ \\ x"= \frac{3-1}{2} = \frac{2}{2} =1 \\ \\ S=\{1,2\}$