Question

Obtenha as coordenadas do vertice da parábola representada pela funçao y=x²-12x+30.

Answer 1

$y= x^{2} -12x+30$ 

a=1
b=-12
c=30

Δ=b²-4ac
Δ=(-12)²-4(1)(30)
Δ=144-120
Δ=24

coordenadas do vértice

$V(X_V,Y_V)=V(6,-6) \\ \\ \\ X_V= \frac{-b}{2a} = \frac{-(-12)}{2} = \frac{12}{2} =6 \\ \\ Y_V= \frac{-\Delta}{4a} = \frac{-24}{4} =-6$