Question

2a2+3b+1=0 em formulá de bhaskara

Answer 1

2a² + 3b + 1 = 0

A = 2
B = 3
C = 1

Δ = b² - 4ac
Δ = (3)² - 4.2.1
Δ = 9 - 8
Δ = 1

X = -b ± √Δ / 2.\a
X = -3 ± √1 / 2.2
X' = -3 + 1 / 4
X' = -2/4
X' = -0,5

X''= -3 - 1 / 4
X''= -4/4
X''= -1