Question

Resolva:
l) ax+42x-95=0
m) 2x²-128=0
n) x²-7=0
o) w²-5w+4=0

Answer 1

ax+42x-95=0
(a+42)x=95
x=95/(a+42)
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2$x^{2}$-128=0
2$x^{2}$=128
$x^{2}$=128/2
$x^{2}$=64
x=$\sqrt{64}$
x=8
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$x^{2}$-7=0
$x^{2}$=7
x=$\sqrt{7}$
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equação do segundo grau, vai ter duas respostas w1 e w2
$w^{2}$-5w+4=0
Δ=$b^{2} -4.a.c$
Δ=$(-5)^{2}-4.1.4$
Δ=25-16=9
w1=-b+$\sqrt{delta}$/2.a
w1=-(-5)+$\sqrt{9}$/2.1
w1=5+3/2=8/2=4

w2=-b-$\sqrt{delta}$/2.a
w2=-(-5)-$\sqrt{9}$/2.1
w2=5-3/2=2/2=1