Question

simplifique os radicais:

Answer 1

$a) \sqrt{48} = \sqrt{2^2.2^2.3} =2.2 \sqrt{3} =4 \sqrt{3} \\ \\ 48|2 \\ 24|2 \\ 12|2 \\ ..6|2 \\ ..3|3 .. \\ ..1$ 

$b) \\ \sqrt[3]{72} = \sqrt[3]{2^3.3^2} =2 \sqrt[3]{9} \\ \\ 72|2 \\ 36|2 \\ 18|2 \\ ..9|3 \\ ..3|3 \\ ..1$ 

$c) \\ \sqrt[3]{162} = \sqrt[3]{2.3^3.3} =3 \sqrt[3]{6} \\ \\ 162|2 \\ ..81|3 \\ ..27|3 \\ ....9|3 \\ ....3|3 \\ ...1$ 

$d) \\ \sqrt[4]{208} = \sqrt[4]{2^4.13} =2 \sqrt[4]{13} \\ \\ 208|2 \\ 104|2 \\ ..52|2 \\ ..26|2 \\ ..13|13 \\ ..1$ 

$e) \\ \sqrt[3]{x^6.y^9.z^{12}} =x^2.y^3.z^4$