Question

M= 3^2 . (4/3 - 1) n= 0,5 + 0,33333... P= 2^-2+3^-1 . qual o valor de m+2n-p?

Answer 1

Vamos la irmao.

$M=3^2.(4/3-1)$
$M=9.(1/3)$
$M=9/1.1/3$
$M=9/3$
$M=3$

Agora vamos achar N.

$N=0,5+0,33$
$N=0,833$

Agora valor de P.

$P=2^{-2}+3+3^{-1}$
$P=(1/2)^2+3/1+1/3$
$P=1/4+3/1+1/3$
$P=16/4+1/3$
$P=4/1+1/3$
$P=13/3$

$M+2.N-P=3+2.0,833-13/3$
$3+2.0,833-13/3=3+1,666-4,333$
$3+1,666-4,333=4,666-4,333$
$4,666-4,333=0,333 ou 0,3$