Question

Determine as coordenadas do vertice da parabola definida pelas funçoes quadraticas
A)y=2x ao quadrado +6x
B)y=-2x ao quadrado +4x-8
C)y=-x ao quadrado +6x-9
D)Y=x ao quadrado-16

Calculo se possivel por favor agradeço desde ja :D

Answer 1

a) y=2x^2+6x
2x^2+6x=0
delta=b^2-4.a.c
delta=6^2-4.2.0
delta=36-0
delta=36
xv=-b/2a
xv=-6/2.2
xv=-6/4 :(2)
xv=-3/2
yv=- delta/4a
yv=-36/4.2
yv=-36/8
yv=-4,5
b) y=-2x^2+4x-8
-2x^2+4x-8=0
delta=b^2-4.a.c
delta=4^2-4.(-2).(-8)
delta=16-64
delta=-48
xv=-b/2a
xv=-4/2.(-2)
xv=-4/-4
xv=1
yv=- delta/4a
yv=-(-48)/4.(-2)
yv=48/-8
yv=-6
c) y=-x^2+6x-9
x^2+6x-9=0
delta=b^2-4.a.c
delta=6^2-4.1.(-9)
delta=36+36
delta=72
xv=-b/2a
xv=-6/2.1
xv=-6/2
xv=-3
yv=- delta/4a
yv=-72/4.1
yv=-72/4
yv=-18
d) y=x^2-16
x^2-16=0
delta=b^2-4.a.c
delta=0^2-4.1.(-16)
delta=0+64
delta=64
xv=-b/2a
xv=-0/2.1
xv=-0/2
xv=0
yv=- delta/4a
yv=-64/4.1
yv=-64/4
yv=-16