Question

COMO DERIVA ESSA FUNÇÃO f(x)=(x³-3x) (2x²+3x+5)?

Answer 1

f´(x) = 3x² + 9x + cos x f'(0) = 3*0² + 9*0 + cos 0 f'(0) = 0 + 0 + 1 f'(0) = 1. 

Answer 2

u = (x³-3x)

v=(2x²+3x+5)

y' = vu' + uv'

y' = (2x²+3x+5). (3x²-3) + (x³-3x)(4x+3)

y' = 6x^4 -6x² +9x³-9x +15x²-15   +   4x^4+3x³-12x² -9x

y' = 10x^4 + 12x³ -3x² -18x -15