Question

Sendo p(x)=x2-5x+3, obtenha o valor numérico de p para :

Answer 1

Olá, Helenabacelar!

p(x) = x² - 5x + 3

a) x=0

p(0) = 0² - 5.0 + 3
p(0) = 0 - 0 + 3
p(0) = 3

b) x=1

p(1) = 1² - 5.1 + 3
p(1) = 1 - 5 + 3
p(1) = 1 - 2
p(1) = -1

c) x = 1+i

p(1+i) = (1+i)² - 5.(1+i) + 3
p(1+i) = 1 + 2.1.i + i² - 5 - 5i + 3
p(1+i) = 1 + 2i + i² - 5 - 5i + 3
p(1+i) = i² + 2i - 5i + 3 - 5 + 1
p(1+i) = i² - 3i - 2 + 1
p(1+i) = i² - 3i - 1

d) x+i