Question

C=[cij]2×2, tal que cij= 1/3 × j+i

Answer 1

c11=1/3x1+1=1/3x2=2/3
c12=1/3x1+2=1/3x3=3/3=1
c21=1/3x2+1=1/3x3=3/3=1
c22=1/3x2+2=1/3x4=4/3