• Matéria: Matemática
  • Autor: marusei
  • Perguntado 8 anos atrás

1)Resolva:
a.- (\frac{1}{3} )^{8}
b.(3)^{-5}
c. -(0,8)^{2}
d.(\frac{4}{3})^{-3}

Respostas

respondido por: nicky10001
1
a) -(1/3)^8 =
= -(1^8/3^8) =
= -(1/6561) =
= -1/6561

b) 3^(-5) =
= (1/3)^5 =
= (1^5/3^5) =
= 1/243

c) -(0,8)^2 =
= -(8/10)^2 =
= -(8^2/10^2) =
= -(64/100) =
= -0,64

d) (4/3)^(-3) =
= (3/4)^3 =
= 3^3/4^3 =
= 27/64
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