• Matéria: Matemática
  • Autor: Ainteligenteboa
  • Perguntado 8 anos atrás

Calcule as expressões

A) 6+7\8 :21/4-5/3

B) 1/7-49/27: (7/3)3

Respostas

respondido por: mariocezar
2
a)
 \frac{1}{6}  +  \frac{7}{8}   \div  \frac{21}{4}  -  \frac{5}{3}  \\  \\  \frac{1}{6}  +  \frac{7}{8}  \times  \frac{4}{21}  -  \frac{5}{3}  \\  \\  \frac{1}{6}  +  \frac{1}{2}  \times  \frac{1}{3}  -  \frac{5}{3}  \\  \\  \frac{1}{6}  +  \frac{1}{6}  -  \frac{5}{3}  \\  \\  -  \frac{4}{3}


b)

 \frac{1}{7}  -  \frac{49}{27}  \div ( \frac{7}{3} )^{3}  \\  \\  \frac{1}{7}  -  \frac{7^{2} }{3 ^{3} }  \div  \frac{7^{3} }{3 ^{3} }  \\  \\  \frac{1}{7}  -  \frac{7^{3} }{3^{3} }  \times  \frac{3^{3} }{7^{3} }  \\  \\  \frac{1}{7}  -  \frac{1}{7}  \\  \\ 0
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