Question

resolva a equação x²+2x+1-9=0

Answer 1

Por ''bháskara'': x²+2x-8=0
Δ=b²-4ac ⇒ Δ = 2²-4(.1)(-8) ⇒ Δ= 4+32 ⇒ Δ=36 ⇒ √36 = 6
x=(-2+-6)/2 
x1=(-2+6)/2 ⇒ x1=4/2 ⇒ x1 =2
x2=(-2-6)/2 ⇒ x2= -8/2 ⇒ x2=-4