Respostas
respondido por:
2
a. Elimination
x+y = 0 Ix2 --> 2x+2y = 0
2x-3y = 4 Ix1 --> 2x-3y = 4
----------------- eliminated
2y-(-3y) = 0-4
2y+3y = -4
5y = -4
y = -4/5
x+y = 0 Ix3 --> 3x+3y = 0
2x-3y = 4 ix1 --> 2x -3y = 4
---------------- +
3x+2x = 0+4
5x = 4
x = 4/5
{ 4/5 e -4/5}
b. 5x+3y = 8
x-2y = -1
Carmel :
5 3
1 -2
det : 5(-2) - 3(1) = -10-3 = -13
8 3
-1 -2
det x : 8(-2) - 3(-1) = -16+3 = -13
5 8
1 -1
det y : 5(-1) -8(1) = -5-8= - 13
x= det x / det = -13/-13 = 1
y= det y / det = -13/-13 = 1
x+y = 0 Ix2 --> 2x+2y = 0
2x-3y = 4 Ix1 --> 2x-3y = 4
----------------- eliminated
2y-(-3y) = 0-4
2y+3y = -4
5y = -4
y = -4/5
x+y = 0 Ix3 --> 3x+3y = 0
2x-3y = 4 ix1 --> 2x -3y = 4
---------------- +
3x+2x = 0+4
5x = 4
x = 4/5
{ 4/5 e -4/5}
b. 5x+3y = 8
x-2y = -1
Carmel :
5 3
1 -2
det : 5(-2) - 3(1) = -10-3 = -13
8 3
-1 -2
det x : 8(-2) - 3(-1) = -16+3 = -13
5 8
1 -1
det y : 5(-1) -8(1) = -5-8= - 13
x= det x / det = -13/-13 = 1
y= det y / det = -13/-13 = 1
respondido por:
4
a) x+y=o
2x-3y= 4
x + y = 0 -------------ISOLAR o (x)
x = - y --------substitituir o (x)
2x - 3y = 4
2(-y) - 3y = 4
- 2y - 3y = 4
- 5y = 4
y = 4/-5
y = - 4/5
----------ACHAR o valor de (x)
x = - y
x = -(4/5)
x = + 4/5
x = 4/5
y = - 4/5
V = { 4/5; -/4/5}
b) { 5x+3y=8
{ x-2y=1
x - 2y = 1---------------> ISOLAR o (x)
x = 1 + 2y ----------> substituir o (x)
5x + 3y = 8
5(1 + 2y) + 3y = 8
5 + 10y + 3y = 8
5 + 13y = 8
13y = 8 - 5
13y = 3
y = 3/13 -------------------> ACHAR o valor de (x)
x = 1 + 2y
x = 1 + 2(3/13)
x = 1 + 6/13
6
x = 1 + ------
13
13 + 6
x = -------------
13
19
x = -------
3
x = 19/3
y = 3/13
V = { 19/13; 3/13}
2x-3y= 4
x + y = 0 -------------ISOLAR o (x)
x = - y --------substitituir o (x)
2x - 3y = 4
2(-y) - 3y = 4
- 2y - 3y = 4
- 5y = 4
y = 4/-5
y = - 4/5
----------ACHAR o valor de (x)
x = - y
x = -(4/5)
x = + 4/5
x = 4/5
y = - 4/5
V = { 4/5; -/4/5}
b) { 5x+3y=8
{ x-2y=1
x - 2y = 1---------------> ISOLAR o (x)
x = 1 + 2y ----------> substituir o (x)
5x + 3y = 8
5(1 + 2y) + 3y = 8
5 + 10y + 3y = 8
5 + 13y = 8
13y = 8 - 5
13y = 3
y = 3/13 -------------------> ACHAR o valor de (x)
x = 1 + 2y
x = 1 + 2(3/13)
x = 1 + 6/13
6
x = 1 + ------
13
13 + 6
x = -------------
13
19
x = -------
3
x = 19/3
y = 3/13
V = { 19/13; 3/13}
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