Question

resolvas as seguintes equacoes fatoriais (n+1)!/(n-1)!=12

Answer 1

$\dfrac{(n+1)!}{(n-1)!}=12\\\\\\\dfrac{(n+1)(n)(n-1)!}{(n-1)!}=12\\\\\\(n+1)(n)=12\\\\n^2+n=12\\\\n^2+n-12=0\\\\n=-4\ ou\ n=3$


Como n nao pode ser negativo, n=3