Question

expresse na escala F a temperatura de 9C

Answer 1

$\frac{Tc}{5 }$ = $\frac{Tf - 32}{9}$

$\frac{9}{5}$ = $\frac{Tf - 32}{9}$

9 . (9) = 5 . (Tf - 32)

81 = 5Tf - 160

81 + 160 = 5Tf

241 = 5 Tf

$\frac{241}{5}$ = Tf

Tf = 48,2