Question

considere a funçao f(x)=x2-2x+1 determine

a)f(-1)
b)f(1)
c)f(-2)
d)f(t)

Answer 1

1^2-2.1+1=0
1-2+1=0
0=0

Answer 2

 f(x)=x2-2x+1 determine

a)f(-1) = (-1)2-2(-1)+1==> 1+2+1 ==> 4
b)f(1) = (1)2-2(1)+1==> 1- 2+1 ==> 0
c)f(-2) = (-2)2-2(-2)+1==> 4+8+1 ==> 13
d)f(t) = (t)2-2(t)+1==> t^2 + 2t + 1