Question

interpole 8 meios aritméticos entre 26 e -1

Answer 1

a 1 = 26
a 10 = -1
n = 10
a 10 = a 1 + (n - 1 ).r
a 10 = 26 + (10 - 1 ).r
a 10 = 26 . 9 r
-1 = 26. 9 r
-1 - 26 = 9 .r
-27 = 9 r
-27 / 9 = r
r = - 3
a 2 = a 1 + r ⇒26 - 3 = 23
a 3 = a 2  + r ⇒23 - 3 = 20
a 4 = a 3 + r  ⇒20 - 3 = 17
a 5 = a 4 + r ⇒17 - 3 = 14
a 6 = a 5 + r ⇒14 - 3 = 11
a 7 = a 6 + r ⇒ 11 - 3 = 8
a 8 = a 7 + r ⇒8 - 3 = 5
a 9 = a 8 + r ⇒5 - 3 = 2
a 10 = a 9 + r ⇒2 - 3 = - 1

 P.A.(26,23,20,17,14,11,8,5,2,-1 )