Question

RESOLUÇÃO PARA 4 QUESTÕES MATEMÁTICAS.

Answer 1

$06. \\ a) (2,5)^-2= (\frac{1}{2,5} )^2= \frac{1}{2,5^2} \\ \\ b)(0,15)^-3= ( \frac{1}{0,15})^3= \frac{1}{0,15^3}$

$07. a) \frac{3,6.10^4}{10^-2.1,2}= \frac{3,6.10^4}{7,6} = \frac{36000}{7,6} = 4736,8= 4,7.10^4$

$b) \frac{2,1.10^-2}{10^-3.0,7} = \frac{21.10^-1}{7.10^-2} =3.10$


$08) 1,99.10^-^2^6.10^3=1,99.10^-^2^3$


$09)\sqrt{ \frac{81}{4} } - \sqrt{400} + \sqrt{2,25} = \frac{9}{2} - 20+ \sqrt{ \frac{225}{100} }= \\ \\ \frac{9}{2} + \frac{15}{10} -20= \frac{45+15}{10}-20= 6-20=-14$