calcule em cada das seguintes funções o f(-2) , f(0) , f( ) e f(4) ::::
A) f(x)=3x²-9
B) f(x)=x²-5x+10
me ajudem por favor ?????w
Respostas
respondido por:
1
Calcule em cada das seguintes funções o
f(-2) , f(0) , f(2/3) e f(4)
A) f(x)=3x²-9
f(-2)
f(x) = 3x²- 9
f(-2) = 3(2)² - 9
f(-2) = 3(4) - 9
f(-2) = 12 - 9
f(-2) = 3
f(0)
f(x) = 3x² - 9
f(0) = 3(0)² - 9
f(0) = 3(0) - 9
f(0) = 0 - 9
f(0) = - 9
f(2/3)
f(x) = 3x² - 9
f(2/3) = 3(2/3)² - 9
f(2/3) = 3(2²/3²) - 9
f(2/3) = 3(4/9) - 9
f(2/3) = 3(4)/9 - 9
f(2/3) = 12/9 - 9
12
f(2/3) = ------- - 9
9
1(12) - 9(9)
f(2/3)= ----------------------
9
12 - 81
f(2/3) = --------------
9
- 69
f(2/3) = -------------
9
f(2/3) = - 69/9
B) f(x)=x²-5x+10
f(-2) , f(0) , f(2/3) e f(4)
f(-2)
f(x) = x² - 5x + 10
f(-2) = (-2)² - 5(-2) + 10
f(-2) = +4 + 10 + 10
f(-2) = 24
f(0)
f(x) = x² - 5x + 10
f(0) = 0² - 5(0) + 10
f(0) = 0 - 0 + 10
f(0) = 10
f(2/3)
f(x) = x² - 5x + 10
f(2/3) = (2/3)² - 5(2/3) + 10
f(2/3) = (2²/3²) - 5(2)/3 + 10
f(2/3) = 4/9 - 10/3 + 10
4 10
f(2/3) = ------- - --------- + 10 mmc 9,3| 3
9 3 3,1| 3
1,1/ = 3x3 = 9
1(4) - 3(10) + 9(10)
f(2/3) = -----------------------------
9
4 - 30 + 90
f(2/3) = -----------------
9
94 - 30
f(2/3) = ------------------
9
64
f(2/3) = --------
9
f(4)
f(x) = x² - 5x + 10
f(4) = (4)² - 5(4) + 10
f(4) = 16 - 20 + 10
f(4) = 26-20
f(4) = 6
me ajudem por favor ?????w
f(-2) , f(0) , f(2/3) e f(4)
A) f(x)=3x²-9
f(-2)
f(x) = 3x²- 9
f(-2) = 3(2)² - 9
f(-2) = 3(4) - 9
f(-2) = 12 - 9
f(-2) = 3
f(0)
f(x) = 3x² - 9
f(0) = 3(0)² - 9
f(0) = 3(0) - 9
f(0) = 0 - 9
f(0) = - 9
f(2/3)
f(x) = 3x² - 9
f(2/3) = 3(2/3)² - 9
f(2/3) = 3(2²/3²) - 9
f(2/3) = 3(4/9) - 9
f(2/3) = 3(4)/9 - 9
f(2/3) = 12/9 - 9
12
f(2/3) = ------- - 9
9
1(12) - 9(9)
f(2/3)= ----------------------
9
12 - 81
f(2/3) = --------------
9
- 69
f(2/3) = -------------
9
f(2/3) = - 69/9
B) f(x)=x²-5x+10
f(-2) , f(0) , f(2/3) e f(4)
f(-2)
f(x) = x² - 5x + 10
f(-2) = (-2)² - 5(-2) + 10
f(-2) = +4 + 10 + 10
f(-2) = 24
f(0)
f(x) = x² - 5x + 10
f(0) = 0² - 5(0) + 10
f(0) = 0 - 0 + 10
f(0) = 10
f(2/3)
f(x) = x² - 5x + 10
f(2/3) = (2/3)² - 5(2/3) + 10
f(2/3) = (2²/3²) - 5(2)/3 + 10
f(2/3) = 4/9 - 10/3 + 10
4 10
f(2/3) = ------- - --------- + 10 mmc 9,3| 3
9 3 3,1| 3
1,1/ = 3x3 = 9
1(4) - 3(10) + 9(10)
f(2/3) = -----------------------------
9
4 - 30 + 90
f(2/3) = -----------------
9
94 - 30
f(2/3) = ------------------
9
64
f(2/3) = --------
9
f(4)
f(x) = x² - 5x + 10
f(4) = (4)² - 5(4) + 10
f(4) = 16 - 20 + 10
f(4) = 26-20
f(4) = 6
me ajudem por favor ?????w
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