Question

determine o 13* termo da PG(64,32,16,...)

Answer 1

Olá, caro colega.

Temos:

$a_1= 64 \\ a_2= 32 \\ n= 13 \\ \\ \\ \boxed{q= \frac{a_2}{a_1}} --> \frac{32}{64}= \boxed{0,5}$

Pelo termo geral, aplique:

$\boxed{\boxed{a_n= a_1*q ^{n-1}}} \\ \\ a_1_3= 64*(0,5) ^{13-1} \\ a_1_3= 64*(0,5) ^{12} \\ a_1_3= 64*0,000244140625 \\ \boxed{\boxed{a_1_3= 0,015625}}$

Bons estudos!