Question

voces pode me ajudar

Answer 1

$g) \sqrt{16x^8} = \sqrt{4^2* x^{2}* x^{2}* x^{2} * x^{2} } =4*x*x*x*x=\boxed{4x^4} \\ h) \sqrt{64am}= \sqrt{8^2*am} = \boxed{8\sqrt{am} } \\ i) \sqrt{100 x^{2} y^{10}} = \sqrt{10^2* x^{2} *y^{10}} =\boxed{10xy^5}$