Question

Equação exponencial :P

$(0,5)^{ \frac{3x-1}{4} } = \frac{1}{8}$

Answer 1

Veja que 0,5 = 1/2 = 2^-1 e 1/8 = 2^-3

2^-1(3x-1)/4 = 2^-3

2^(-3x+1)/4 = 2^-3

(-3x+1)/4=-3
-3x+1=-12
3x=1+12
3x=13
x=13/3

Answer 2

$(0,5)^{ \frac{3x-1}{4}}= \frac{1}{8} \\ \\ (\frac{5}{10}) ^\frac{3x-1}{4}= \frac{1}{8} \\ \\ (\frac{1}{2}) ^\frac{3x-1}{4}= \frac{1}{8} \\ \\ (\frac{\not1}{2}) ^\frac{3x-1}{4}= (\frac{\not1}{2})^3 \\ \\ \frac{3x-1}{4}=3 \\ \\ 3x-1=4*3 \\ 3x-1=12 \\ 3x=12+1 \\ 3x=13 \\ x= \frac{13}{3}$

S:{13/3}