Question

simplifique os radicais

Answer 1

$\sqrt{400} = \sqrt{2^4.5^2} =2^2.5=4.5=20 \\ \\ \sqrt{1600} = \sqrt{2^6.5^2} =2^3.5=8.5=40 \\ \\ \sqrt[3]{125} = \sqrt[3]{5^3} =5$