Question

No triângulo retângulo da figura, calcule;

Answer 1

a)

$sen\ \theta=\frac{CO}{H}\\\\ \boxed{sen\ \theta=\frac{3}{5}}$

b)

$cos\ \theta=\frac{CA}{H}\\\\ \boxed{cos\ \theta=\frac{4}{5}}$

c)

$tg\ \theta=\frac{CO}{CA}\\\\ \boxed{tg\ \theta=\frac{3}{4}}$