Question

resolva a equação usando bhaskara
(x-5)^2=1

Answer 1

(x-5)^2=1 > x² - 5x - 5x +25 - 1 > = x² -10x + 24 = 0
a = 1
b = -10
c = 24

Bhaskara:
Δ = b²-4*a*c = (-10)² - (4*1*24) > 100 - 96 >  Δ = 4

x = ( -b ± √Δ ) / 2*a > ( -(-10) ± √4 ) / 2*1 > (10 ± 2) / 2
x' = 10 + 2 / 2 = 12/2 = 6
x'' = 10 - 2 / 2 = 8/2 = 4

x = {6, 4}