Question

3^x-5=27^1-x ????




lll

Answer 1

    x - 5           1 - x
3           =   27 

    x - 5           3 (1 - x)
3           =    3

Cortamos as duas bases (3):

x - 5 = 3(1 - x)
x - 5 = 3 - 3x
x + 3x = 3 + 5
4x = 8
x = 8/4
x = 2

Answer 2

$3^{x-5}=27^{1-x}$
$3^{x-5}=(3^3)^{1-x}$
$3^{x-5}=3^{3-3x}$ cancelamos as bases iguais

$x-5 = 3-3x$
$x+3x = 3+5$
$4x = 8$
$x = \frac{8}{4}$
$x=2$