Question

Calcule o valor das medidas insixadas
nos triângulos retângulos indicadas

Answer 1

$sen 60^o = \dfrac{ \sqrt{3}}{2} \\ \\ \\ \dfrac{ \sqrt{3}}{2} = \dfrac{12 \sqrt{3}}{a} \\ \\ \\ \sqrt{3}a = 2 * 12\sqrt{3} \\ \\ \\ \sqrt{3}a = 24 \sqrt{3} \\ \\ \\ a = \dfrac{24 \sqrt{3}}{ \sqrt{3}} \\ \\ \\ a = 24$

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$cos60^o = \dfrac{1}{2} \\ \\ \\ \dfrac{1}{2} = \dfrac{b}{24} \\ \\ \\ 2b = 24 \\ \\ \\ b = \dfrac{24}{2} \\ \\ \\ b = 12$