Question

logaritimo de 4 na base 1/8

Answer 1

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$\log_{ \frac{1}{8} }4=x \\ \\ ( \frac{1}{8} )^x=4 \\ \\ 8^{-x}=4 \\ \\ 2^{-3x}=2^2 \\ \\ -3x=2 \\ \\ 3x=-2 \\ \\ x=- \frac{2}{3}$

Answer 2

$log_{ \frac{1}{8} }4=x$

$(\frac{1}{8})^x=4$

$(\frac{1}{2^3})^x=2^2$

$(2^{-3})^x=2^2$

$2^{-3x} = 2^2$

$-3x=2$

$x=- \frac{2}{3}$

Espero ter ajudado.