• Matéria: Matemática
  • Autor: marasales9294
  • Perguntado 8 anos atrás

(4√28-3√63×5√2-(√2+6√23)×2√7.como resolver passo em passo

Respostas

respondido por: Kæzar
0
Olá.

4\sqrt28-(3\sqrt63*5\sqrt2) - [(\sqrt2+6+\sqrt23)*(2\sqrt7)]\\\\
4\sqrt{4}\sqrt7 - (3\sqrt{7}\sqrt9*5\sqrt2) - (2\sqrt2\sqrt7+12\sqrt7+2\sqrt{23}\\\\
4.2\sqrt7 - (3.3\sqrt7 * 5\sqrt2) - (2\sqrt 2\sqrt7+12\sqrt7+2\sqrt23)\\\\
8\sqrt7 - (45\sqrt7\sqrt2) - (2\sqrt2\sqrt7+12\sqrt7+2\sqrt23)\\\\
8\sqrt7-45\sqrt7\sqrt2-2\sqrt2\sqrt7-12\sqrt7-2\sqrt23\\\\
8\sqrt7-43\sqrt7\sqrt2-12\sqrt7-2\sqrt23\\\\
-4\sqrt7-43\sqrt7\sqrt2-2\sqrt23\\\\
(\sqrt7)(-4-43\sqrt2)-2\sqrt23
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