Question

efetue a divisão abaixo:

(x+1/x-2 + x-3/x+2) : 2x²-2x+8/x-2

Answer 1

$\frac{ \frac{x+1}{x-2} + \frac{x-3}{x+2}}{ \frac{2x^2-2x+8}{x-2} } = \frac{ \frac{+1}{-2} + \frac{-3}{+2}}{ \frac{2x-2x+8}{-2} } = \frac{ \frac{+1}{-2} + \frac{-3}{+2}}{ \frac{+8}{-2} } = \frac{ \frac{+1}{-2} + \frac{-3}{+2}}{ -4 } = \frac{ \frac{-4}{2}}{ -4 } = \frac{-2}{ -4 } = \frac{1}{2}$