Question

Considerando as aproximações log 2 = 0,3 e log 3 = 0,48.

Calcule: log∛1,8

Answer 1

$log( \sqrt[3]{1,8})=log(1,8)^{\frac{1}{3}} =\frac{1}{3}log(1,8)=\frac{1}{3}log(0,2*0,3*0,3)=\\ \\ \frac{1}{3}(log0,2+log0,3+log0,3)=\frac{1}{3}(0,3+0,48+0,48)=\\ \\ \frac{1}{3}*1,26=0,42$