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Se for como está na imagem:
![6\sqrt{256} - 12 \sqrt[3]{4096} + \sqrt[9]{512}=\\\\
Como:\\
\sqrt{256}=16\\
\sqrt[3]{4096}=16\\
\sqrt[9]{512}=2\\\\
Assim:\\\\
6\sqrt{256} - 12 \sqrt[3]{4096} + \sqrt[9]{512}=6.16-12.16-2=96-192+2=-94](https://tex.z-dn.net/?f=6%5Csqrt%7B256%7D+-+12+%5Csqrt%5B3%5D%7B4096%7D+%2B+%5Csqrt%5B9%5D%7B512%7D%3D%5C%5C%5C%5C%0AComo%3A%5C%5C%0A%5Csqrt%7B256%7D%3D16%5C%5C%0A+%5Csqrt%5B3%5D%7B4096%7D%3D16%5C%5C%0A%5Csqrt%5B9%5D%7B512%7D%3D2%5C%5C%5C%5C%0AAssim%3A%5C%5C%5C%5C%0A6%5Csqrt%7B256%7D+-+12+%5Csqrt%5B3%5D%7B4096%7D+%2B+%5Csqrt%5B9%5D%7B512%7D%3D6.16-12.16-2%3D96-192%2B2%3D-94 "6\sqrt{256} - 12 \sqrt[3]{4096} + \sqrt[9]{512}=\\\\
Como:\\
\sqrt{256}=16\\
\sqrt[3]{4096}=16\\
\sqrt[9]{512}=2\\\\
Assim:\\\\
6\sqrt{256} - 12 \sqrt[3]{4096} + \sqrt[9]{512}=6.16-12.16-2=96-192+2=-94")
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