Question

B- log²/³(4x+5)-log2/3(6x-9)=0

Answer 1

$\mathrm{\ell og_{^{2}\!\!\diagup\!\!_{3}}}{\left(4x+5\right)}-\mathrm{\ell og_{^{2}\!\!\diagup\!\!_{3}}}{\left(6x-9\right)}=0\\ \\ \mathrm{\ell og_{^{2}\!\!\diagup\!\!_{3}}}{\left(4x+5\right)}=\mathrm{\ell og_{^{2}\!\!\diagup\!\!_{3}}}{\left(6x-9\right)}\\ \\ 4x+5=6x-9\\ \\ 4x-6x=-9-5\\ \\ -2x=-14\\ \\ x=\dfrac{-14}{-2}\\ \\ \boxed{x=7}$