• Matéria: Matemática
  • Autor: revengedani
  • Perguntado 8 anos atrás

O valor da expressão sen 30° + cos 30° - cos 60°/tag60° é:

Respostas

respondido por: Rich0031
2
sen 30° + cos 30° - cos 60°/tg 60°

 \frac{  \cancel{\frac{1}{2}}  +  \frac{ \sqrt{3} }{2}   -   \cancel{\frac{1}{2}} }{ \sqrt{3} }  =  \frac{ \frac{ \sqrt{3} }{2} }{ \sqrt{3} }  =  \frac{  \cancel{\sqrt{3}} }{2 \cancel{ \sqrt{3}} }  =  \frac{1}{2}
respondido por: PNiel
1
Olá!

\ \ \ \ \ \ \ \ \ \ \left[\begin{array}{ccccc}30\°\end{array}\right] \left[\begin{array}{ccccc}45\°\end{array}\right]\left[\begin{array}{ccccc}60\°\end{array}\right] \end{array}\right] \\ \\sen:\ \ \ \ \ \ \frac{1}{2}\ \ \ \ \ \ \ \ \frac{\sqrt{2}}{2} \ \ \ \ \ \ \ \frac{ \sqrt{3} }{2} \\ \\cos:\ \ \ \ \ \frac{ \sqrt{3} }{2}\ \ \ \ \ \ \ \frac{\sqrt{2}}{2}\ \ \ \ \ \ \ \ \ \frac{1}{2}\\ \\tg:\ \ \ \ \ \ \ \frac{\sqrt{3}}{3}\ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \sqrt{3}

\dfrac{(1/2) + \frac{\sqrt{3}}{3} - (1/2)}{ \sqrt{3} }\\ \\ \\\dfrac{\frac{\sqrt{3}}{2}}{ \sqrt{3} }\\ \\ \\\ \frac{1}{2}

Qualquer dúvida comente ;)
Bons estudos!
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