Question

Derive g=(3-x2) (x2-x+1)

Answer 1

$g(x)=(3-x^2)(x^2-x+1)\\ \\ g(x)=3x^2-3x+3-x^4 +x^3-x^2\\ \\ \boxed{g(x)=-x^4+x^3+2x^2-3x+3} \\ \\ \boxed{g'(x)=-4x^3+3x^2+4x-3}$