Question

Responda essa equaçao
(4X+3)·(X-2)=3X·(4x+1)

Answer 1

$(4x + 3) \times (x - 2) = 3x \times (4x + 1) \\ {4x}^{2} - 8x + 3x - 6 = {12x}^{2} + 3x \\ {4x}^{2} - {12x}^{2} - 8x + 3x - 3x = 6 \\ { - 8x}^{2} - 8x = 6 \\ { - 8x}^{2} - 8x + 6 = 0 \\ {8x}^{2} + 8x - 6 = 0 \: simplificando \: por \: 2 \\ {4x}^{2} + 4x - 3 = 0 \\ a = 4 \: b = 4 \: c = - 3 \\ delta = {4}^{2} - 4 \times 4 \times ( - 3) \\ delta = 16 + 48 \\ delta = 64 \\ \sqrt{64} = 8 \\ x1 = \frac{ - 4 + 8}{8} \\ x1 = \frac{1}{2} \\ x2 = \frac{ - 4 - 8}{8} \\ x2 = - \frac{3 }{2}$