• Matéria: Matemática
  • Autor: rodrigocalraozq3tz
  • Perguntado 8 anos atrás

Inicialmente sabemos que uma matriz quadrada 2 x 2 com elementos reais,que tenha o formato open vertical bar table row a cell negative b end cell row b a end table close vertical bar´ possui autovalores complexos lambda space equals space a space plus-or-minus space i b Na forma polar o autovalor complexo lambda pode ser escrito como a space equals space open vertical bar lambda close vertical bar space cos ϕ space e space b space equals space open vertical bar lambda close vertical bar space s e n ϕ spacedessa forma podemos escrever:

Assinale a alternativa correta que representa o resultado da escrita.

Escolha uma:
a. open square brackets table row a cell negative b end cell row a a end table close square brackets space equals space open square brackets table row cell open vertical bar lambda close vertical bar end cell a row a cell open vertical bar lambda close vertical bar end cell end table close square brackets space
b.
open square brackets table row a cell negative b end cell row a a end table close square brackets space equals space open square brackets table row cell cos open parentheses ϕ close parentheses end cell cell negative s e n o open parentheses ϕ close parentheses end cell row cell s e n o open parentheses ϕ close parentheses end cell cell cos open parentheses ϕ close parentheses end cell end table close square brackets

c. open square brackets table row cell negative a end cell cell negative b end cell row a cell negative a end cell end table close square brackets space equals space open square brackets table row cell open vertical bar lambda close vertical bar end cell a row a cell open vertical bar lambda close vertical bar end cell end table close square brackets space open square brackets table row cell s e n o left parenthesis ϕ right parenthesis end cell cell negative cos space left parenthesis phi right parenthesis end cell row cell cos left parenthesis ϕ right parenthesis end cell cell s e n left parenthesis space phi right parenthesis end cell end table close square brackets
d. open square brackets table row a cell negative b end cell row b a end table close square brackets space equals space open square brackets table row cell open vertical bar lambda close vertical bar end cell 0 row 0 cell open vertical bar lambda close vertical bar end cell end table close square brackets space open square brackets table row cell cos space open parentheses ϕ close parentheses end cell cell negative s e n open parentheses ϕ close parentheses end cell row cell s e n open parentheses ϕ close parentheses end cell cell cos open parentheses ϕ close parentheses end cell end table close square brackets

e.
open square brackets table row a cell cos phi end cell row a cell s e n empty set end cell end table close square brackets space equals space open square brackets table row b a row a cell negative b end cell end table close square brackets space open square brackets table row cell negative b end cell cell negative s e n o open parentheses ϕ close parentheses end cell row a cell cos open parentheses ϕ close parentheses end cell end table close square brackets

Respostas

respondido por: icaroiko05p67vc2
53
Resposta correta , letra C


Anexos:

Anônimo: Correta!
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