Question

Qual e o perimetro de um terreno quadrado cuja a area é 806,52 m cubicos?

Answer 1

A = 806,52 m²       A = L² ------ 806,52 = L² ----- L = √806,52   ------ L = 28,399

P = 4L ------- P = 4 . 28,399 ------ P = 113,596 m

Answer 2

$A=L^{2}$
$806,52=L^{2}$
$L= \sqrt{806,52}$
$L=28,36$

$Perimetro$
$P=4L$
$P=4*28,36$
$P=113,44$