Question

x²+8x+16=25 resolva com a fórmula de bháskara

Answer 1

x²+8x+16-25=0
x²+8x-9=0
a=1
b=8
c=-9

Δ=8²-4.1.(-9)
=64-(-36)
=100
x= (-8+-10)/2

x1=-9
x2=1