• Matéria: Física
  • Autor: alvarovcarvalho
  • Perguntado 9 anos atrás

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Anexos:

Respostas

respondido por: aawr
1
Bom,i1 é a corrente inicial,portanto é a soma de todas as correntes que se dividiram:
i1 = 3+2+8 = 13 A

Já i2 é a soma das correntes equivalentes a 2 A e a 8A:
i2 = 2+8 = 10 A

alvarovcarvalho: valeu
aawr: :)
alvarovcarvalho: :3
respondido por: emillyschadeck05
0

Resposta:

i1 = 3+2+8 = 13 A

i2 = 2+8 = 10 A

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