• Matéria: Matemática
  • Autor: Bibsbarrs
  • Perguntado 8 anos atrás

preciso de ajuda nas equações com log!! pfv

Anexos:

Respostas

respondido por: francof23
1
\dfrac{1-\frac{\log x}{2}}{\log x^2}=\dfrac{\log x}{\log x^4}\\\\\\1-\dfrac{\log x}{2}=\dfrac{(\log x^2)(\log x)}{\log x^4}\\\\\\2-\log x=\dfrac{2(\log x^2)(\log x)}{\log x^4}\\\\\\2-\log x=\dfrac{2(2\log x)(\log x)}{4\log x}\\\\\\2-\log x=\log x\\\\\\2\log x=2\\\\\\\log x=1\\\\10^1=x\\\\\x=10

Bibsbarrs: muito obrigada
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