Question

calcule os logaritmos em cada caso: a) log2 32 b) log0,5 2

Answer 1

$a) \\ \log_232=x \\ \\ 2^x=32 \\ 2^x=2^5 \\ x=5 \\ \\ \log_232=5 \\ \\ b) \\ \log_{0,5}2=x \\ \\ (0,5)^x=2 \\ ( \frac{5}{10} )^x=2 \\ \\ ( \frac{1}{2} )^x=2 \\ \\ 2^{-x}=2^1 \\ -x=1~~\times(-1) \\ x=-1 \\ \\ log_{0,5}2=-1$