Question

a função inversa de y= x-1/2x+1, x diferente de - 1/2, é dada por:

Answer 1

$y=\frac{x-1}{2x+1}\\ \\ x=\frac{y-1}{2y+1}\\ \\ x(2y+1)=y-1\\ \\ 2xy+x=y-1\\ \\ 2xy-y=-x-1\\ \\ y(2x-1)=-x-1\\ \\ \boxed{y=\frac{-x-1}{2x-1}}$