Question

${x}^{2} + 10x = - 16$
Como resolver?? Bháskara

Answer 1

${x}^{2} + 10x + 16 = 0$
a 1
b 10
c 16

Delta =
${ b }^{2} - 4.a.c$
Delta =
${10}^{2} - 4.1.4.16$
Delta =
$100 - 64$
Delta =
$36$