Question

Calcule a medida do lado AC do triangulo ABC, sabendo que AB= 20√2

Answer 1

180 - 105 - 30 = 45O  angulo B = 45º Lei dos SenosAC/sen45º = 10√2/sen30ºAC/√2/2 = 10√2/1/2fazendo cruz1/2×AC = √2/2×10√21/2×AC = 10√4/21/2×AC = 10×2/21/2×AC = 20/21/2×AC = 10AC = 10/1/2AC = 10×2/1AC = 20/1AC = 20